8h^2+9h-1224=0

Solution for 8h^2+9h-1224=0 equation:

8h^2+9h-1224=0

a = 8; b = 9; c = -1224;
Δ = b2-4ac
Δ = 92-4·8·(-1224)
Δ = 39249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{39249}=\sqrt{441*89}=\sqrt{441}*\sqrt{89}=21\sqrt{89}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-21\sqrt{89}}{2*8}=\frac{-9-21\sqrt{89}}{16}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+21\sqrt{89}}{2*8}=\frac{-9+21\sqrt{89}}{16}
$